Log2(5x-1) - (3/(log2(5x-1)-1) + 1= 0
Предположим log2 (5x-1)=y y-(3/y-1)+1=0 (y+1)=3/y-1 y^2-1=3 y^2=4 y1=+2 y2=-2 log2(5x-1)=2 log2(5x-1)=-2 5x-1=4 5x-1=1/4 x=1 x=1/4