X^6-x^8/x^4-x^2 и второй b^7-b^10/b^9-b^3 ( ^ степень)

Question

X^6-x^8/x^4-x^2 и второй b^7-b^10/b^9-b^3 ( ^ степень)

Answer 1

1) =x^6(1 -x²) /x²(x² -1) = -x^4(x² -1) /(x² -1) = -x^4

2) =b^7(1 -b^3) /b^3(b^6 -1) = -b^4(b^3 -1) /(b^3 -1)(b^3 +1) = -b^4 /(b^3 +1)