sinα sinβ
1+ -------- * -------
cosα cosβ cosα cosβ+ sinα sinβ cos(α-β)
1)...= -------------------------- = --------------------------------- = ----------------
sinα sinβ cosα cosβ - sinα sinβ cos(α+β)
1- --------*-------
cosα coβ
2)
sin3α+ sin³α (3 sinα-4sin³α) +sin³α 3sinα(1-sin²α) 3sinα*cos²α
---------------------- = ------------------------------- = ---------------------- = ------------------ =
cos³α- cos3α cos³α-(4cos³α-3cosα) 3cosα(1-cos²α) 3 cosα*sin²α
= tgα * ctg²α= (tgα*ctgα)*ctgα=1*ctgα=ctgα