4/1,6=7х-2/10,4 срочно пж!

Решите задачу:

$\frac{4}{1}* \frac{10}{16} = 7x- \frac{2}{1}* \frac{10}{104}; \frac{10}{4} =7x - \frac{10}{52}; 7x= \frac{10}{52}+ \frac{10}{4}= \frac{1*10}{52}+ \frac{13*10}{52}$ $\frac{4}{1,6} = 7x- \frac{2}{10,4}; \frac{4}{1}: \frac{16}{10}=7x- \frac{2}{1}: \frac{104}{10}; \frac{4}{1}* \frac{10}{16} = 7x- \frac{2}{1}* \frac{10}{104};$ $7x=\frac{10+130}{52}= \frac{140}{52} = \frac{35}{13}; x= \frac{35}{13}:7= \frac{35}{13}* \frac{1}{7} = \frac{5}{13}; x= \frac{5}{13}.$