2y²-5y+2=2(y-1/2)(y-2)=(2y-1)(y-2)
D=25-16=9
y1=(5-3)/4=1/2
y2=(5+3)/4=2
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1)(3y-2)(3y+2)/[(2y-1)(y-2)] *(2-y)/(3y+2)=-(3y-2)/(2y-1)=(3y-2)/(1-2y)
2)(3y-2)/(1-2y)+y/(1-2y)=(3y-2+y)/(1-2y)=(4y-2)/(1-2y)=-2(1-2y)/(1-2y)=-1