1)27a^3+8b^3-(3a+2b)(9a^2+6ab+4b^2) при a=-1 b=12)(x-4b)(x^2 +4xb+16b^2)+64b^3+x+b^2 при...

Question

1)27a^3+8b^3-(3a+2b)(9a^2+6ab+4b^2) при a=-1 b=1
2)(x-4b)(x^2 +4xb+16b^2)+64b^3+x+b^2 при х=-1,b=2

Answer 1

27a^3+8b^3-(3a+2b)(9a^2+6ab+4b^2)=27*(-1)^3+8*1^3-(3*(-1)+2*1)(9*(-1)^2+6*(-1)*1+4*1^2)=-27+8-(-3+2)(9-6+4)=-27+8-(-1)*7=-19+7=-12

(x-4b)(x^2 +4xb+16b^2)+64b^3+x+b^2=x^3-64b^3+64b^3+x+b^2=x^3+x+b^2=(-1)^3-1+2^2=-1-1+4=2