Решите уравнение 2 (x^3+1) = 7 (x^2-1)
2*(х+1)(х²-х+1)-7(х-1)(х+1)=0 (х+1)(2*(х²-х+1)-7(х-1))=0 (х+1)(2х²-2х+2-7х+7)=0 (х+1)(2х²-9х+9)=0 х+1=0 или 2х²-9х+9=0 D=(-9)²-4*2*9=81-72=9 х=-1 x1=9+√9)/2*2= (9+3)/4=3 x2=9-3)/4=6/4=3/2=1.5 jndtn -1. 1.5 3