(√5-а)(√5+а) (b+√с)(4√с-b) (√z-√7)(√z+√7) (√2m+√11n)(√11n-√2m)

Question

(√5-а)(√5+а)
(b+√с)(4√с-b)
(√z-√7)(√z+√7)
(√2m+√11n)(√11n-√2m)

Answer 1

(-a))=5-2a+
(√z-√7)=z-2√7z+7
(√2m-√11n)=2m-2√22mn+11n