(2х+1)(х+4)-3х(х+2)<0 </p>
Решите неравенство
(2х+1)(х+4)-3х(х+2)<0 </span>
2x^2+9x+4-3x^2-6x<0</span>
-x^2+3x+4<0</span>
D=3^2-4*-1*4=25 √D=5 x1=(-3-5)/(2*-1)=4 x2=(-3+5)/(2*-1)=-1
Ответ: (-∞;-1)v(4;+∞)
=2х^2+8х+х+4-3х^2-6х <0</p>
-х^2+3х+4<0</p>