Помогите с задачей. Упростить выражение (9/m^2-3m+9 + 2m/3+m - m^3-15m^2/m^3+27)*(m+3 -...

Решите задачу:

$( \frac{9}{m^{2} -3m+9} + \frac{2m}{3+m} - \frac{m^{3}-15m^{2}}{m^{3}+27} )*(m+3 - \frac{9m}{m+3} ) * \frac{1}{m+3} = \\ = \frac{9(3+m) + 2m(m^{2} -3m+9) -(m^{3}-15m^{2}) }{m^{3}+27} *( 1 - \frac{9m}{(m+3)^{2}} )= \\ = \frac{27+9m + 2m^{3} -6m^{2}+18m -m^{3}+15m^{2} }{m^{3}+27} * \frac{(m+3)^{2} - 9m}{(m+3)^{2}} = \\ = \frac{m^{3} + 9m^{2}+27m+27 }{m^{3}+27} * \frac{m^{2}+6m+9 - 9m}{(m+3)^{2}} = \\ = \frac{ (m^{3}+27) +(9m^{2}+27m) }{m^{3}+27} *\frac{m^{2}-3m+9}{(m+3)^{2}} = \\$
$= \frac{ (m+3)*(m^{2}-3m+9) +(m+3)*9m }{m^{3}+27} *\frac{m^{2}-3m+9}{(m+3)^{2}} = \\ = \frac{ (m+3)*(m^{2}-3m+9+9m) }{m^{3}+27} *\frac{m^{2}-3m+9}{(m+3)^{2}} = \\ = \frac{ (m+3)*(m^{2}+6m+9)*(m^{2}-3m+9) }{(m^{3}+27)*(m+3)^{2}} = \\ = \frac{ (m+3)*(m+3)^{2}*(m^{2}-3m+9) }{(m^{3}+27)*(m+3)^{2}} = \\ = \frac{ (m+3)*(m^{2}-3m+9) }{m^{3}+27} = \\ = \frac{ m^{3}+27 }{ m^{3}+27} = 1 \\$