Cos^2 (2014x) = sin^2 (2014 x);
cos^2(2014x) - sin^2(2014x) = 0;
(cos(2014x) - sin(2014x) *(cos(2014x) + sin(2014x)) = 0;
1) cos (2014x) = sin(2014x); / cos(2014x) ≠ 0;
tg(2014x) = 1;
2014 x = pi/4 + pi*k;
x = pi/8416 + pik/ 2014; k ∈ Z.
2) cos(2014x) = - sin(2014x); / cos(2014x) ≠ 0;
tg(2014 x) = - 1;
x = - pi/4 + pi*k;
x = - pi/8416 + pi/2014; k∈Z.
Объединив 2 ответа, получим
x = + - pi/8416 + pi*k / 2014; k ∈ Z
вроде все)