5x\\ x^2-x-12>0\\ D=-1^2-4*1*(-12)=49\ \ \ \sqrt{D}=7\\ x1=(1-7)/2=-3\\ x2=(1+7)/2=4\\ Answer:(-\infty;-3)\cup(4;+\infty)" alt="x^2+4x-12>5x\\ x^2-x-12>0\\ D=-1^2-4*1*(-12)=49\ \ \ \sqrt{D}=7\\ x1=(1-7)/2=-3\\ x2=(1+7)/2=4\\ Answer:(-\infty;-3)\cup(4;+\infty)" align="absmiddle" class="latex-formula">