cos x = 1/2 x=±arccos 1/2 + 2 Pi*nn=1, n=2, n= -1, n= 0.

Question

cos x = 1/2

x=±arccos 1/2 + 2 Pi*n
n=1, n=2, n= -1, n= 0.

Comments

а задача то в чем?

Answer 1

N=1
a)
x=-pi/3 + 2 Pi=5pi/3
b)pi/3+2pi=7pi/3
n=2
a)x=-pi/3 + 4 Pi=11pi/3
b)x=pi/3+4pi=13pi/3
n=-1
a)x=-pi/3-2pi=-7pi/3
b)-5pi/3
n=0
a)x=-pi/3
b)x=pi/3