program s1;vara:array [1..10] of integer; i,n,s,p,k1,k2:integer; begin write ('n-?');...

Question

program s1;
var
a:array [1..10] of integer; i,n,s,p,k1,k2:integer;
begin
write ('n-?'); readln(N);
for i:=1 to n do
Begin
Write (i, '-й-?'); readln (a[i]);
end;
for i:=1 to n do write ('', a[i]);
writeln;
s:=0; p:=1; k1:=0; k2:=0; k3:=0;
for i:=1 to n do
begin
{1} s:=s+a[i];
{2} if a[i]>0 then p:=p*a[i];
{3} if a[i]<0 then k1:=k1+1;<br>{4} if a[i] mod 2=0 then k2:=k2+1;
{5} if a[i] mod 2=1 then k3:=k3*i;
end;
writeln ('s=', s, ' p=', p, ' k1=', k1, ' k2=', k2, )
end.

Из этой задачи вывести произведение нечетных чисел в k3

Answer 1

Program s1;
var
a:array [1..10] of integer; i,n,k3:integer;
begin
write ('n-?'); readln(N);
for i:=1 to n do
Begin
Write (i, '-й-?'); readln (a[i]);
end;
for i:=1 to n do write ('', a[i]);
writeln; 
k3:=0;
for i:=1 to n do
begin
if a[i] mod 2=1 then k3:=k3*i;
end;
writeln (' k3=', k3);
end.