решите уравнение 1/x+1/(x+8)=1/3
((х+8)+х)/(х^2+8х)=1/3
(2х+8)/(х^2+8х)=1/3
2х+8=(х^2+8х)/3
3*(2х+8)=х^2+8х
6х+24=х^2+8x
x^2+2x-24=0
D=100
x1=4
x2=-6
(X + 8 + X) \ X*(X+8) = 1\3
3*(2X+8) = X^2 + 8X
6X + 24 = X^2 + 8X
x^2 + 2X - 24 = 0
D = 4 - 4*(-24) + 4 + 96 = 100
X1 = - 2 + 10 \ 2 = 4
X2 = - 12\2 = -6