Обчисліть вираз ............

$(3 \frac{3}{4}* \frac{3}{5}-7 \frac{1}{2}:27+1 \frac{2}{9}):(3 \frac{1}{6}-1 \frac{1}{4})=1 \frac{10}{69}$
1) $3 \frac{3}{4}* \frac{3}{5}= \frac{15}{4}* \frac{3}{5}= \frac{9}{4}=2 \frac{1}{4}$
2) $7 \frac{1}{2}:27= \frac{15}{2*27}= \frac{5}{18}$
3) $2 \frac{1}{4}-\frac{5}{18}+1 \frac{2}{9}=2 \frac{9}{36}- \frac{10}{36}+ \frac{8}{36}=2 \frac{17}{36}- \frac{10}{36}=2 \frac{7}{36}$
4) $3 \frac{1}{6}-1 \frac{1}{4}=3 \frac{2}{12}-1 \frac{3}{12}=2 \frac{14}{12}-1 \frac{3}{12}=1 \frac{11}{12}$
5) $2 \frac{7}{36}:1 \frac{11}{12}= \frac{79}{36}* \frac{12}{23}= \frac{79}{69}=1 \frac{10}{69}$