![image](https://tex.z-dn.net/?f=2x%5E2-+x+-15+%3E0+%5C%5C%5C+D%3D1%2B120%3D121+%5C%5C%5C+x_1%3D+%5Cfrac%7B1%2B11%7D%7B4%7D+%3D3+%5C%5C%5C+x_1%3D+%5Cfrac%7B1-11%7D%7B4%7D+%3D-2.5%0A%5C%5C%5C%0Ax%5Cin+%28-%5Cinfty%3B+-2.5%29%5Ccup+%283%3B+%2B%5Cinfty%29)
0 \\\ D=1+120=121 \\\ x_1= \frac{1+11}{4} =3 \\\ x_1= \frac{1-11}{4} =-2.5
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x\in (-\infty; -2.5)\cup (3; +\infty)" alt="2x^2- x -15 >0 \\\ D=1+120=121 \\\ x_1= \frac{1+11}{4} =3 \\\ x_1= \frac{1-11}{4} =-2.5
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x\in (-\infty; -2.5)\cup (3; +\infty)" align="absmiddle" class="latex-formula">
Ответ: x>3 и x<-2.5</u>