0 \\\ D=1+120=121 \\\ x_1= \frac{1+11}{4} =3 \\\ x_1= \frac{1-11}{4} =-2.5
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x\in (-\infty; -2.5)\cup (3; +\infty)" alt="2x^2- x -15 >0 \\\ D=1+120=121 \\\ x_1= \frac{1+11}{4} =3 \\\ x_1= \frac{1-11}{4} =-2.5
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x\in (-\infty; -2.5)\cup (3; +\infty)" align="absmiddle" class="latex-formula">
Ответ: x>3 и x<-2.5</u>