Сократите дробь b^2-b-6/9b+18

Question

Сократите дробь b^2-b-6/9b+18

Answer 1

B²-b-6=0
b1+b2=1 U b1*b2=-6⇒b1=-2 U b2=3
(b+2)(b-3)/9(b+2)=(b-3)/9