F(x)=x^3+0,5x^2-4x+2 , f'(x)<=0

Question

F(x)=x^3+0,5x^2-4x+2 , f'(x)<=0

Answer 1

F'(x)= 3x^2+x-4+0=3x^2+x-4
3x^2+x-4<=0<br>D= 1+48=49
X1= (1-7)/6=-1
X2=(1+7)/6=4/3
[-1;4/3]