Способом подстановки найдите решение (x0 y0) системы 2y-15x=3 5x-y=-1

Решите задачу:

$\left \{ {{2y-15x=3 } \atop {5x-y=-1}} \right. \left \{ {{2y-15x=3 } \atop {y=5x+1}}} \right. \left \{ {{2(5x+1)-15x=3} \atop {y=5x+1}} \right. \left \{ {{10x+2-15x=3} \atop {y=5x+1} \right. \left \{ {{-5x=3-2} \atop {y=5x+1}} \right.$

$\left \{ {{5x=-1} \atop {y=5x+1}} \right. \left \{ {{x=-0.2} \atop {y=5x+1}} \right. \left \{ {{x=-0.2} \atop {y=5*(-0.2)+1}} \right. \left \{ {{x=-0.2 \atop {y=-1+1}} \right. \left \{ {{x=-0.2} \atop {y=0}} \right.$