Sin(180) × tg(135) - cos(120) = ???

Question

Sin(180) × tg(135) - cos(120) = ???

Answer 1

Sin180°•tg(135°) - cos120° = 0•(-tg45°) + cos(180° - 120°) = cos60° = 1/2.

Comments

-1/2

Answer 2

Ответ: - 0.5
Sin180(0)X tg135-(0.5)=-0.5

Comments

-cos120° = -(-cos(180° - 120°) = cos60° = 1/2.

---

-1+1/2=-1/2

---

Ошибся. Ответ будет 1/2