Друзья помогите решить . y²-6=0 y²- 1/3=0 y²-1,7=0 -18= -y² y²=1/125

1) y² - 6 = 0
y² = 6
y = $\sqrt{6}$

2) y² - $\frac{1}{3}$ = 0

y² = $\frac{1}{3}$

y = $\sqrt{ \frac{1}{3}} = \frac{1}{ \sqrt{3}} = \frac{ \sqrt{3}}{3}$

3) y²-1,7 = 0
y² = 1,7
y² = $\sqrt{1,7}$

4) -18= -y²
y² = 18
y = $\sqrt{18} = \sqrt{9*2} = \sqrt{3*3*2} = 3 \sqrt{2}$

5) y² = $\frac{1}{125}$

y = $\sqrt{ \frac{1}{125}} = \frac{1}{ 5\sqrt{5}} = \frac{ \sqrt{5} }{25}$