6(x+1)²+2(x-1)(x²+x+1)-2(x+1)³ =26

Question

6(x+1)²+2(x-1)(x²+x+1)-2(x+1)³ =26

Answer 1

6(x+1)²+2(x-1)(x²+x+1)-2(x+1)³-26=0
6(x²+2x+1)+2(x-1)(x²+x+1)-2(x³+3x²+3x+1)-26=0
(6x²+12x+6)+(2x-2)(x²+x+1)-(2x³+6²+6x+2)-26=0
(6x²+12x+6)+(2x³-2)-(2x³+6x²+6x+2)-26=0
(6x²+12x+6+2x³-2-2x³-6x²-6x-2-26=0
6x-24=0
6x=24
x=24÷6
x=4