Решите систему уравнений
(x-y)(x^2+xy+y^2)=8 x-y=2 x^2+xy+y^2=4 x-y=2 x=y+2 (y+2)^2+(y+2)*y+y^2=4 y^2+2y+4+y^2+2y+y^2-4=0 3y^2+4y-4=0 D=64; y1=-4+8/6=4/6=2/3 y2=-2; x1=2/3+2=8/3 x2=-2+2=0 Ответ: (8/3;2/3) и (0;-2)