Tg4x=√3/3 4x=π/3+πk x=π/12+πk/4
надо найти решения ∈[ -π;π]
k=0 π/12
k=1 π/12+π/4=π/3
k=-1 π/12-π/4=-π/6
k=2 π/12+π/2=7/12π
k=-2 π/12-π/2=-5π/12
k=3 π/12+3/4π=5π/6
k=-3 π/12-3π/4=-π/3
k=4 π/12+4π/4>π
k=-4 π/12-π=-11π/12
k=-5 π/12-5π/4=-14π/12<-π<br>-------------------------
решения выделены жирным.