1) х2-5х+6 2) 5y2-3y2-2

Question

1) х2-5х+6

2) 5y2-3y2-2

Answer 1

1)  х2-5х+6=0
D = 25-24 =1
x= 1/2 (5 +/- 1)
x1 =2
x2 =3
ОТВЕТ  x ={2;3}

2)  5y2-3y2-2 = 2y2 - 2 = 2(y-1)(y+1)=0
y1 =1
y2=-1
ОТВЕТ y={-1;1}