Решить логарифмическое неравенство:

Question 1

Question 2

$x*3^{log_{_{\frac{1}{9}}}(16x^4-8x^2+1)}\ \textless \ \frac{1}{3} \\ODZ:16x^4-8x^2+1\ \textgreater \ 0 \\Tochki\ peresecheniya: 16x^4-8x^2+1=0 \\C\ TEOPEMbI\ BUETA: x^2=\frac{4}{16} \\x^2=\frac{1}{4} \\x=\pm\frac{1}{2} \\Esli\ x=-1,\ to\ 16x^4-8x^2+1=16-8+1=9 \\Esli\ x=0,\ to\ 16x^4-8x^2+1=1 \\Esli\ x=1,\ to\ 16x^4-8x^2+1=9\ (funktsiya\ parnaya) \\ODZ: x\neq \pm\frac{1}{2}$
$x*3^{log_{_{\frac{1}{9}}}(16x^4-8x^2+1)}\ \textless \ \frac{1}{3} \\x*3^{{log_{_{3^{-2}}}}(16(x-\frac{1}{4})^2)}}}}\ \textless \ \frac{1}{3} \\x*3^{-\frac{1}{2}log_{_3}(4(x-\frac{1}{4}))^2}\ \textless \ \frac{1}{3} \\x*3^{{-log_{_3}}(4(x-\frac{1}{4}))}}\ \textless \ \frac{1}{3} \\\frac{x}{3^{{log_{_3}}(4x-1)}}}\ \textless \ \frac{1}{3} \\\frac{x}{4x-1}\ \textless \ \frac{1}{3} \\\frac{x}{4x-1}-\frac{1}{3}\ \textless \ 0 \\\frac{3x-4x+1}{3(4x-1)}\ \textless \ 0 \\\frac{1-x}{12x-3}\ \textless \ 0 \\imeem\ sovokupnost'\ sistem: \\ \left \{ {{1-x\ \textless \ 0} \atop {12x-3\ \textgreater \ 0}} \right. \ \ \ ili\ \ \left \{ {{1-x\ \textgreater \ 0} \atop {12x-3\ \textless \ 0}}$
$\\ \left \{ {{1-x\ \textless \ 0} \atop {12x-3\ \textgreater \ 0}} \right. \ \ \ ili\ \ \left \{ {{1-x\ \textgreater \ 0} \atop {12x-3\ \textless \ 0}} \right. \\ \left \{ {{x\ \textgreater \ 1} \atop {12x\ \textgreater \ 3}} \right.\ \ \ \ \ \ \ \ \ \ \ \ \left \{ {{x\ \textless \ 1} \atop {12x\ \textless \ 3}} \right. \\\left \{ {{x\ \textgreater \ 1} \atop {x\ \textgreater \ \frac{3}{12}}} \right.\ \ \ \ \ \ \ \ \ \ \ \ \left \{ {{x\ \textless \ 1} \atop {x\ \textless \ \frac{3}{12}}} \right. \\\left \{ {{x\ \textgreater \ 1} \atop {x\ \textgreater \ \frac{1}{4}}} \right.\ \ \ \ \ \ \ \ \ \ \ \ \ \left \{ {{x\ \textless \ 1} \atop {x\ \textless \ \frac{1}{4}}} \right. \\x\ \textgreater \ 1\ \ \ \ \ \ \ ili\ \ \ \ \ x\ \textless \ \frac{1}{4}$
$Uchitivaem\ ODZ:\ x\neq \pm \frac{1}{2} \\OTBET: x\in \{(-\infty;-\frac{1}{2});(-\frac{1}{2};\frac{1}{4});(1;+\infty)$
Графическое решение на изображении

Question 3

А как это записать всё?

Question 4

Разобралась,извините)