Sin(arccos(-1/2)-arctg(-1/√3)+ARCCOS(-1/2)

Question

Sin(arccos(-1/2)-arctg(-1/√3)+ARCCOS(-1/2)

Answer 1

Sin(2 arccos(-1/2)-2 arctg√3)=sin(2*2П/3-2*п/3)=sin(4п/3-2п/3)=sin2п/3=√3/2 может так