Решите уравнения (задания прикреплены)

Решение:

a) $\sqrt{5}$ × $5^{3x}$ = $\frac{1}{5}$
$5^{ \frac{1}{2} }$ × $5^{3x}$ = $5^{-1}$
   $5^{ \frac{1+6x}{2} } = 5^{-1}$
   $\frac{1+6x}{2}=-1$
1+6x=-2
6x=-2-1
6x=-3
x= $- \frac{3}{6} =- \frac{1}{2}$

b) $4^{x}$ -3× $4^{x-2}$ =52
   $4^{x}-3$ × $4^{x}$ × $4^{-2}$ =52
$4^{x}-3* 4^{x}* \frac{1}{16}$ =52
   $4^{x}$ - $\frac{3}{16}$ × $4^{x}$ =52
( $1- \frac{3}{16}$ )× $4^{x}$ =52
   $\frac{13}{16}$ × $4^{x}$ =52
   $\frac{16}{13}$ × $\frac{13}{16}$ × $4^{x}$ = $\frac{16}{13}$ ×52
$4^{x}$ =64
$4^{x}$ = $4^{3}$
x=3

в) $16^{ \frac{x+5}{2} }=0.25$ × $128^{x-2}$
   $2^{4 * \frac{x+5}{2} }$ = $\frac{1}{4} * 2^{7(x-2)}$
   $2^{2x+10}= 2^{-2}*2^{7x-14}$
   $2^{2x+10}= 2^{7x-16}$
2x+10=7x-16
2x-7x=-16-10
-5x=-26
x= $\frac{26}{5} =5.2$