Знайти границю lim(5x2+3x+7) x->0.5

Question

Знайти границю

lim(5x2+3x+7)

x->0.5

Answer 1

0,5}(5x^2+3x+7)=\frac{\lim}{x->0,5}(5*0,5^2+3*0,5+7)=9,75" alt="\frac{\lim}{x->0,5}(5x^2+3x+7)=\frac{\lim}{x->0,5}(5*0,5^2+3*0,5+7)=9,75" align="absmiddle" class="latex-formula">