Помогите пожалуйста [tex](3- \sqrt{2})*(5+ \sqrt{8})=? (4- \sqrt{3})*( \sqrt{3}+6)=? (2+...

Решите задачу:

$(3- \sqrt{2})*(5+ \sqrt{8})=15+3\sqrt8-5\sqrt2-\sqrt{16}=\\ =15+6\sqrt2-5\sqrt2-4=11+\sqrt2\\ \\ (4- \sqrt{3})*( \sqrt{3}+6)=4\sqrt3+24-3-6\sqrt3=21-2\sqrt3\\ \\ (2+ \sqrt{15})*( \sqrt{5}- \sqrt{3}) =2\sqrt5-2\sqrt3+\sqrt{75}-\sqrt{45}=\\ =2\sqrt5-2\sqrt3+5\sqrt{3}-3\sqrt{5}=3\sqrt3-\sqrt5\\ \\$

$(3 \sqrt{5}+ \sqrt{3)}*( \sqrt{3}-4 \sqrt{5})=3\sqrt{15}-12*5+3-4\sqrt{15}=\\ =-\sqrt{15}-57\\ \\ (x- \sqrt{y})*(3x-4 \sqrt{y} )=3x^2-4x\sqrt y-3x\sqrt y+4y=3x^2+4y-7x\sqrt y\\\\ ( \sqrt{x} +3 \sqrt{y})*( \sqrt{y}-4 \sqrt{x} )=\sqrt{xy}-4x+3y-12\sqrt{xy}=3y-4x-11\sqrt{xy}\\ \\ (2 \sqrt{a}+ \sqrt{b})*( \sqrt{a}-5 \sqrt{b})=2a-10\sqrt{ab}+\sqrt{ab}-5b=2a-5b-9\sqrt{ab}\\ \\ (4 \sqrt{a}-7 \sqrt{b})*(2 \sqrt{b}-3 \sqrt{a})=8\sqrt{ab}-12a-14b +21\sqrt{ab}=\\=29\sqrt{ab}-12a-14b$