Решите уравнение (х2-4)(х2+х-2)=0
( x² - 4 )( x² + x - 2 ) = 0 x² - 4 = 0 ( x - 2 )( x + 2 ) = 0 x - 2 = 0 x = 2 x + 2 = 0 x = - 2 x² + x - 2 = 0 D = 1 + 8 = 9 ; √ D = 3 x1 = ( - 1 + 3 ) : 2 = 1 x2 = ( - 1 - 3 ) : 2 = - 2 Ответ 2 ; - 2 ; 1