2x²-2 --------------- 3x²+6x+3 сократите дробь
(2х^2 - 2)/(3х^2 + 6х + 3) = 2(х^2-1)/3(х^2 + 2х + 1) = 2(х-1)(х+1)/3(х+1)(х+1) = 2(х-1)/3(х+1) = (2х-2)/(3х+3).
2(x²-1)/3(x+1)²=2(x-1)(x+1)/3(x+1)(x+1)=2x-2/3x+3