Как решить эту систему неравенств?

$\left \{ {{6-2x\ \textless \ 3(x-1)} \atop {6- \frac{x}{2} \geq x}} \right. \left \{ {{6-2x\ \textless \ 3x-3} \atop {12-x \geq 2x}} \right. \left \{ {{-5x\ \textless \ -9} \atop {-3x \geq -12}} \right. \left \{ {{x\ \ \textgreater \ \frac{5}{9} } \atop {x \leq 4}} \right.$ $\left \{ {{---( \frac{5}{9} )+++++++++\ \textgreater \ x } \atop {++++++++++[4]---\ \textgreater \ x }} \right$
x∈ $( \frac{5}{9};4]$
Ответ: $1;2;3;4$