Делайте срочно@@@@@@@@@@@@@

Question

Делайте срочно@@@@@@@@@@@@@

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Answer 1

49) = ( - 2Cosx +3Sinx) | в пределах от π/4 доπ/2 =
=-2Сosπ/2 +3Sinπ/2 -( -2Сosπ/4 + 3Sinπ/4) = 0 +3 +2*√2/2 -3*√2/2 =3-√2/2
50) = (2Sinx +3Cosx)| в пределах от π/6 до π/3 =
=2Sinπ/3 + 3Cosπ/3 -( 2Sinπ/6 +3Cosπ/6) = √3 +3/2 -1 -3√3/2 = 1/2 -√3/2