РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ!!!7 КЛАСС АЛГЕБРА,РЕБЯЯЯТ,ПООМОГИТЕ,ПО-БРАТСКИ!

Решите задачу:

$1)\; \; \left \{ {{ \frac{x}{3}-\frac{y}{2}=8\; |\cdot 6} \atop { \frac{3x}{8}+\frac{y}{4} =22\; |\cdot 8}} \right. \; \left \{ {{2x-3y=48\; |\cdot 3} \atop {3x+2y=176\; |\cdot (-2)}} \right. \; \left \{ {{2x-3y=48} \atop {-13y=-208}} \right. \\\\ \left \{ {{2x-3\cdot 16=48} \atop {y=16}} \right. \; \left \{ {{2x=96} \atop {y=16}} \right. \; \left \{ {{x=48} \atop {y=16}} \right.$

$2) \left \{ {{ \frac{m+1}{5} -\frac{3n-5}{10}=-2\; |\cdot 10} \atop { \frac{m-3}{6} +\frac{5n-9}{4}=2,5\; \cdot 12}} \right. \; \; \left \{ {{2(m+1)-(3n-5)=-20} \atop {2(m-3)+3(5n-9)=30}} \right. \; \; \left \{ {{2m+2-3n+5=-20} \atop {2m-6+15n-27=30}} \right.$

$\left \{ {{2m-3n=-27} \atop {2m+15n=63}} \right. \; \ominus \; \left \{ {{2m-3n=-27} \atop {-18n=-90}} \right. \; \; \left \{ {{2m-3\cdot 5=-27} \atop {n=5}} \right. \\\\ \left \{ {{2m=-12} \atop {n=5}} \right. \; \; \left \{ {{m=-6} \atop {n=5}} \right.$