Найдите х из пропорции!!!!
(27-3b)/(25-5b) = (ab+3a)/10bx (27-3b).10bx = (ab+3a)(25-5b) 10bx=a(b+3).5(5-b)/3(9-b) 10bx=5a(b+3)(5-b)/3(9-b) x=5a(b+3)(5-b)/30b(9-b) x=a(b+3)(5-b)/6b(9-b) x=a(b+3)(b-5)/6b(b-9), b≠5,b≠0,b≠9,a≠0