Y=(t^4/4)-(t^3/3)-6*t^2+2*t+1 t=2 сек a(t)=?

Question

Y=(t^4/4)-(t^3/3)-6*t^2+2*t+1 t=2 сек a(t)=?

Answer 1

V(t)=Y'(t)=t³-t²-12t+2
a(t)=V'(t)=Y"(t)=3t²-2t-12
a(2)=3*4-4-12=-4