Завтра сессия, нужно с решением
5) 6.arctg(-√3)=2π/3+2πk,k∈z x/2-π/2=2π/3 x/2=2π/3+π/2=7π/6 x=7π/6*2=14π/6=7π/3 Ответ:x=7π/3+2πk,k ∈z
![\sqrt[4]{x^4y^4}=(x^4y^4)^ \frac{1}{4}=xy
\sqrt{xy}=(xy )^ \frac{1}{2}
\sqrt{x^2}=x
(xy)^ \frac{1}{2}*x=x^ \frac{3}{2}y^ \frac{1}{2}
xy:x^ \frac{3}{2}y \frac{1}{2}
x^(1-1.5)=x^- \frac{1}{2}=1/ \sqrt{x}
y^(1-1/2)=1^1/2= \sqrt{y}
1/ \sqrt{x} * \sqrt{y}= \sqrt{y}/ \sqrt{x} =( \frac{y}{x})^ \frac{1}{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B4%5D%7Bx%5E4y%5E4%7D%3D%28x%5E4y%5E4%29%5E+%5Cfrac%7B1%7D%7B4%7D%3Dxy%0A+%0A%5Csqrt%7Bxy%7D%3D%28xy+%29%5E+%5Cfrac%7B1%7D%7B2%7D%0A%0A+%5Csqrt%7Bx%5E2%7D%3Dx%0A%0A%28xy%29%5E+%5Cfrac%7B1%7D%7B2%7D%2Ax%3Dx%5E+%5Cfrac%7B3%7D%7B2%7Dy%5E+%5Cfrac%7B1%7D%7B2%7D%0A%0Axy%3Ax%5E+%5Cfrac%7B3%7D%7B2%7Dy+%5Cfrac%7B1%7D%7B2%7D%0A%0Ax%5E%281-1.5%29%3Dx%5E-+%5Cfrac%7B1%7D%7B2%7D%3D1%2F+%5Csqrt%7Bx%7D%0A%0Ay%5E%281-1%2F2%29%3D1%5E1%2F2%3D+%5Csqrt%7By%7D%0A%0A1%2F+%5Csqrt%7Bx%7D+%2A+%5Csqrt%7By%7D%3D+%5Csqrt%7By%7D%2F+%5Csqrt%7Bx%7D+%3D%28+%5Cfrac%7By%7D%7Bx%7D%29%5E+%5Cfrac%7B1%7D%7B2%7D++++ "\sqrt[4]{x^4y^4}=(x^4y^4)^ \frac{1}{4}=xy
\sqrt{xy}=(xy )^ \frac{1}{2}
\sqrt{x^2}=x
(xy)^ \frac{1}{2}*x=x^ \frac{3}{2}y^ \frac{1}{2}
xy:x^ \frac{3}{2}y \frac{1}{2}
x^(1-1.5)=x^- \frac{1}{2}=1/ \sqrt{x}
y^(1-1/2)=1^1/2= \sqrt{y}
1/ \sqrt{x} * \sqrt{y}= \sqrt{y}/ \sqrt{x} =( \frac{y}{x})^ \frac{1}{2}")