Помогите с подробным решением

0\; ,\; y>0" alt="1)\; \; \left \{ {{log_3x+log_3y=log_34+2} \atop {2^{log_2(x+y)}=5log_216}} \right. \; ,\quad ODZ:\; \; x>0\; ,\; y>0" align="absmiddle" class="latex-formula">

$\left \{ {{log_3(xy)=log_34+log_33^2} \atop {x+y=log_2(2^4)^5}} \right. \; \left \{ {{log_3(xy)=log_3(4\cdot 9)} \atop {x+y=log_22^{20}}} \right. \\\\ \left \{ {{xy=36} \atop {x+y=20}} \right. \; \left \{ {{x(20-x)=36} \atop {y=20-x}} \right. \; \left \{ {{x^2-20x+36=0} \atop {y=20-x}} \right. \; \left \{ {{x_1=2\; ,\; x_2=18} \atop {y_1=18\; ,\; y_2=2}} \right. \\\\Otvet:\; \; (2,18)\; ,\; \; (18,2)$

$2)\; \; 4^{\frac{1}{2}log_23+3log_85}=(2^2)^{\frac{1}{2}log_23+3log_{2^3}5}=2^{log_23+2log_25}=\\\\=2^{log_23+log_25^2}=2^{log_2(3\cdot 25)}=3\cdot 25=75$