Помогите решить систему уравнения! Подробно

Решите задачу:

$\left \{ {2(x+y)=8} \atop {14-3(x-y)=5y-x}} \right. \left \{ { 2x+2y=8} \atop {14-3x+3y=5y-x}} \right. \left \{ { 2x=8-2y} \atop {14-3x+3y-5y+x=0}} \right. \left \{ { x= \frac{(8-2y)}{2} } \atop {-3x+3y-5y+x=-14}} \right. \left \{ { x= \frac{(8-2y)}{2} } \atop {-2x-2y=-14}} \right. \left \{ { x= \frac{(8-2y)}{2} } \atop {-2( \frac{(8-2y)}{2})-2y=-14}} \right.$ $\left \{ { x= \frac{8}{2} - \frac{-2y}{2} } \atop {-2( \frac{(8-2y)}{2})-2y=-14}} \right. \left \{ { x=4 + 2y } \atop {-2(4 + 2y)-2y=-14}} \right. \left \{ { x=4 + 2y } \atop {-8 -4y -2y=-14}} \right. \left \{ { x=4 + 2y } \atop {-6y=-6}} \right. \left \{ { x=4 + 2y } \atop {y= \frac{-6}{-6} }} \right. \left \{ { x=4 + 2*1 } \atop {y=1 }} \right. \left \{ { x=6 } \atop {y=1 }} \right.$