Решить систему уравнений

Решите задачу:

$\left \{ {{ \frac{2x-1}{10}=2- \frac{9(y-3)}{20}\; |\cdot 20 } \atop { \frac{y-4}{4}=\frac{2x-9}{3}-\frac{3}{4} \; |\cdot 12}} \right. \; \left \{ {{2(2x-1)=40-9(y-3)} \atop {3(y-4)=4(2x-9)-9}} \right. \; \left \{ {{4x+9y=69\, \cdot (-2)} \atop {8x-3y=33\; \; \; \; \; }} \right. \oplus \\\\ \left \{ {{4x+9y=69} \atop {-21y=-105}} \right. \; \left \{ {{4x=69-9y} \atop {y=5}} \right. \; \left \{ {{x=\frac{1}{4}(69-45)} \atop {y=5}} \right. \; \left \{ {{x=6} \atop {y=5}} \right.$