Решите уравнение 4Cos²x-1=0
4cosx^2-1=0 (2cosx-1)(2cosx+1)=0 2cosx-1=0 cosx=1/2 x=+-pi/3+2pi*n, n∈Z 2cosx+1=0 cosx=-1/2 x=+-2pi/3+2pi*k, k∈Z
4cos(x)^2-1=0 4cos(x)^2=1 cos(x)^2=1/4 cos(x)=1/2 cos(x)=-1/2 x=pi/3 x=2pi/3