Решите уравнение (1/5)^x-1+(1/5)^x+1=650
(1/5)^x-1+(1/5)^x+1=650 пусть(1/5)^x = t, t >0 тогда t - 1 + t + 1 = 650 2t = 650 t = 325 (1/5)^x = 325 x = log 1/5 (325) x = –log 5 (5·5·13) -x = log 5 (5) + log 5 (5) + log 5 (13) -x = 2 + log 5 (13) x = –2 – log 5 (13)