(4а-7)(2)=(4а+3)(4а-3)+58

Question

(4а-7)(2)=(4а+3)(4а-3)+58

Answer 1

8a-14=4a^2+3^2+58
-4a^2+8a-81=0
Дальше корни ищи

Answer 2

(4а-7)2=(4а+3)(4а-3)+58
8а-14=16а^-9+58
8а-14-16а^-49=0
-16a^+8a-63=0
D=64-4(-16)(-63)=64-4032=-3968
D<0,нет корней