Помогите алгебра 10кл
6 log₈² x - 5 log₈ x + 1 = 0 ОДЗ: х > 0 Замена t = log₈ x 6t² - 5t + 1 = 0 D = 25 - 24 = 1 t₁ = (5 - 1)/12 = 4/12 = 1/3 log₈ x₁ = 1/3 -->x₁ = ∛8 = 2 t₂ = (5 + 1)/12 = 6/12 = 1/2 log₈ x = 1/2 -->x₂ = √8 = 2√2 Ответ: x₁ = 2; x₂ = 2√2