4
ОДЗ x-2>0⇒x>2
log(2)[5/(x-2)]>log(2)3
5/(x-2)>3
5/(x-2)-3>0
(5-3x+6)/(x-2)>0
(3x-11)/(x-2)<0<br>x=11/3 x=2
+ _ +
---------------(2)---------------(11/3)--------------------
22
x∈(2;3 2/3)
Ответ х=3
5
ОДЗ x+5>0⇒x>-5
√(x+5)=a
2a-4/a=7
2a²-7a-4=0,a≠0
D=49+32=81
a1=(7-9)/4=-1/2⇒√(x+5)=-1/2 нет решения
a2=(7+9)/4=4⇒√(x+5)=4⇒x+5=16⇒x=11
6
(9/2)^(x-x²)≥(2/9)^(4x+14)
x-x²≥-4x-14
x²-5x-14≤0
x1+x2=5 U x1*x2=-14
x1=-2 U x2=7
+ _ +
-----------------[-2]------------------[7]-------------------
x∈[-2;7]