Log1/3 (5-2x)>-2. Помогите пожалуйста решить

$log_{ \frac{1}{3} } (5-2x)\ \textgreater \ -2$
ОДЗ:
$5-2x\ \textgreater \ 0$
$-2x\ \textgreater \ -5$
$x\ \textless \ 2,5$

$log_{ \frac{1}{3} } (5-2x)\ \textgreater \ log_{ \frac{1}{3} } ( \frac{1}{3})^{ -2}$
$log_{ \frac{1}{3} } (5-2x)\ \textgreater \ log_{ \frac{1}{3} } 9$
$5-2x\ \textless \ 9$
$-2x\ \textless \ 9-5$
$-2x\ \textless \ 4$
$x\ \textgreater \ -2$

-------(-2)-----------------------
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--------------------(2,5)--------
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Ответ: $(-2; 2,5)$