А) (2 - 5x)^(1/2) < 1 {2 - 5x >= 0 -> x <= 2/5}<br>2 - 5x < 1
5x > 1
-> 1/5 < x <= 2/5<br>
б) log25(3-x) < -1/2 {3-x > 0 -> x < 3}
3-x < 25^(-1/2)
3-x < 1/5
x > 14/5
14/5 < x < 3
в) log1/3(log2( (x-1)/(2-x) )) > -1 {(x-1)/(2-x) > 0 --> 1 < x < 2}
log3(log2( (x-1)/(2-x) )) < 1
log2( (x-1)/(2-x) ) < 3
(x-1)/(2-x) < 2^3 = 8
x-1 < 16 - 8x
9x < 17
x < 17/9 < 2
1 < x < 17/9
г) log2(3x + 7) > log2(5x - 1) {3x + 7 > 0, 5x - 1 > 0 -> x > 1/5}
3x+7 > 5x-1
2x < 8
1/5 < x < 4