Уравнение (3х-2)²-(5-3х)(5+3х)=8-6х распишите пожалуйста

Решите задачу:

$(3x-2)^2-(5-3x)(5+3x)=8-6x\\9x^2-2*3*2*x+4-(25-9x^2)=8-6x\\9x^2-12x+4-8+6x-25+9x^2=0\\18x^2-6x-29=0\\\mathtt{D}=(-6)^2-4*18*(-29)=2124=36*59=(\pm6\sqrt{59})^2\\\mathtt{x_1}= \dfrac{6+6\sqrt{59}}{2*18}\ \ \ \ \mathtt{x_1}= \dfrac{1+\sqrt{59}}{6} \\\mathtt{x_2}= \dfrac{6-6\sqrt{59}}{2*18}\ \ \ \ \mathtt{x_2} =\dfrac{1-\sqrt{59}}{6}\\\boxed{\mathcal{OTVET}:\mathtt{x_1}= \dfrac{1+\sqrt{59}}{6};\ \mathtt{x_2}= \dfrac{1-\sqrt{59}}{6}. }$